Magic in XOR

Practice

4 (1 votes)

Easy

Simple Math

Problem

85% Success 409 Attempts 20 Points 0.5s Time Limit 4048MB Memory 1024 KB Max Code

This question is quite simple. You will be given 2 numbers let's say 'A' and 'C' and you have to find a number 'B' such that A (+) B = C. A (+) B = C can be read as A xor B = C. You can read more about XOR operation here: link See Sample test-case for more understanding. Note: In all programming languages, you can XOR two numbers say X and Y by ‘^’ (shift-6) key.

Sample Input

5 6

Sample Output

Explanation

Let's take B as 3: 0101 (decimal 5) XOR 0011 (decimal 3) = 0110 (decimal 6) As we can see that A = 5, C = 6. So as per formula A (xor) B => C. Suppose B = 3, 5 (xor) 3 => 6 is obtained. Hence, B = 3 satisfies formula A xor B = C. Thus, output is 3 as B = 3.

Code Editor

You need to be logged in to access the code editor

Please wait while we load the editor

Submissions

Please login to view your submissions

You need to be logged in to access the code editor

Please wait while we load the editor